x^2+3x+(9/4)=-15/4

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Solution for x^2+3x+(9/4)=-15/4 equation: 


x in (-oo:+oo)

x^2+3*x+9/4 = -15/4 // + -15/4

x^2+3*x+9/4-(-15/4) = 0

x^2+3*x+9/4+15/4 = 0

x^2+3*x+6 = 0

DELTA = 3^2-(1*4*6)

DELTA = -15

DELTA < 0

x belongs to the empty set

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